1、现在有两个列表，list1 = [‘key1 ‘,’key2 ‘,’key3 ‘ ]和list2 = [‘1’,’2’ ,’3’]，把他们转为这样的字典： {‘key1 ‘:’1’,’key2’:’2 ‘,’key3’:’3 ‘ }

list1 = ['key1','key2','key3']
list2 = ['1','2','3']
dict(zip(list1,list2 ) )
{'key1':'1','key2':'2','key3':'3'}

2、将嵌套列表转为字典，有两种方法，

new_list= [['key1','value1'],['key2','value2'],['key3','value3']]
dict(list)
{'key3': 'value3', 'key2': 'value2', 'key1': 'value1'}

或者这样：

new_list= [['key1','value1'],['key2','value2'],['key3','value3']]
new_dict = {}
for i in new_list:
    new_dict[i[0]] = i[1]                #字典赋值，左边为key，右边为value
new_dict
{'key3': 'value3', 'key2': 'value2', 'key1': 'value1'}

https://blog.csdn.net/petib_wangwei/article/details/38685303